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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: a 2 mũ 2. 3 mũ 1 -(1 mũ 2022 + 2021 mũ 0) : 2 b 2020 + [38 – (9-3) mũ 2] – 2030 mũ 0

Toán Lớp 6: a 2 mũ 2. 3 mũ 1 -(1 mũ 2022 + 2021 mũ 0) : 2
b 2020 + [38 – (9-3) mũ 2] – 2030 mũ 0

Comments ( 2 )

  1. $#AS$
    a) 2^2 * 3^1 – (1^2022 + 2021^0) : 2
    = 4 * 3 – (1 + 1) : 2
    = 12 – 2 : 2
    = 12 – 1
    = 11
    b) 2020 + [38 – (9 – 3)^2] – 2030^0
    = 2020 + [38 – 6^2] – 1
    = 2020 + [38 – 36] – 1
    = 2020 + 2 – 1
    = 2022 – 1
    = 2021

  2. Giải đáp+Lời giải và giải thích chi tiết:
    a, 2^2 . 3^1 – (1^2022 + 2021^0):2
    = 4.3-(1+1):2
    = 12-2:2
    = 12-1
    = 11
    b, 2020+[38-(9-3)^2]-2030^0
    = 2020+[38-6^2]-1
    = 2020+[38-36]-1
    = 2020+2-1
    = 2022-1
    = 2021

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222-9+11+12:2*14+14 = ? ( )