## Toán Lớp 6: 1) 135 + 360 + 65 + 24 + 40 2) 8. 4. 34. 125. 25 3) 8. 4. 34. 125. 25 4) 129. 172 – 73. 129 + 129 5) 5.2^3 – 18 : 3^2 6) 205 – [ 1200

Question

Toán Lớp 6: 1) 135 + 360 + 65 + 24 + 40
2) 8. 4. 34. 125. 25
3) 8. 4. 34. 125. 25
4) 129. 172 – 73. 129 + 129
5) 5.2^3 – 18 : 3^2
6) 205 – [ 1200 – (4^2 – 2.3)^3 ] : 40, hướng dẫn giải giúp em bài này ạ, em cảm ơn thầy cô và các bạn nhiều.

in progress 0
6 tháng 2022-06-21T07:16:29+00:00 2 Answers 0 views 0

## TRẢ LỜI ( 2 )

1. #andy
$\begin{array}{l} 1){\rm{ }}135{\rm{ }} + {\rm{ }}360{\rm{ }} + {\rm{ }}65{\rm{ }} + {\rm{ }}24{\rm{ }} + {\rm{ }}40\\ = (135 + 65) + (360 + 40) + 24\\ = 200 + 400 + 24\\ = 600 + 24\\ = 624\\ 2){\rm{ }}8.{\rm{ }}4.{\rm{ }}34.{\rm{ }}125.{\rm{ }}25\\ = (25.8)(125.4).34\\ = 200.500.34\\ = 3400000\\ 4){\rm{ }}129.{\rm{ }}172{\rm{ }} – {\rm{ }}73.{\rm{ }}129{\rm{ }} + {\rm{ }}129\\ = 129.(172 – 73 + 1)\\ = 129.100\\ = 12900\\ 5)\,{5.2^3} – 18:{3^2}\\ = 5.8 – 18:9\\ = 40 – 2\\ = 38\\ 6)205 – [1200 – {({4^2} – 2.3)^3}]:40\\ = 205 – [1200 – {(16 – 6)^3}]:40\\ = 205 – (1200 – {10^3}):40\\ = 205 – (1200 – 1000):40\\ = 205 – 200:40\\ = 200 \end{array}$

2. $@Zeng$
$1)135+360+65+24+40$
$=(135+65)+(360+40)+24$
$=200+400+24$
$=600+24$
$=624$
$2+3)8.4.34.125.25$
$=(8.125).(4.25).34$
$=1000.100.34$
$=100000.34$
$=3400000$
$4)129.172-73.129+129$
$=129(172-73+1)$
$=129(99+1)$
$=129.100$
$=12900$
$5.2^3-18:3^2$
$=5.8-18:9$
$=40-2$
$=38$
$6)205-[1200-(4^2-2.3)^3]:40$
$=205-[1200-(16-2.3)^3]:40$
$=205-[1200-(16-6)^3]:40$
$=205-[1200-10^3]:40$
$=205-[1200-1000]:40$
$=205-200:40$
$=205-5$
$=200$