Toán Lớp 6: 1) 135 + 360 + 65 + 24 + 40 2) 8. 4. 34. 125. 25 3) 8. 4. 34. 125. 25 4) 129. 172 – 73. 129 + 129 5) 5.2^3 – 18 : 3^2 6) 205 – [ 1200

Question

Toán Lớp 6: 1) 135 + 360 + 65 + 24 + 40
2) 8. 4. 34. 125. 25
3) 8. 4. 34. 125. 25
4) 129. 172 – 73. 129 + 129
5) 5.2^3 – 18 : 3^2
6) 205 – [ 1200 – (4^2 – 2.3)^3 ] : 40, hướng dẫn giải giúp em bài này ạ, em cảm ơn thầy cô và các bạn nhiều.

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Cẩm Thúy 2 ngày 2022-06-21T07:16:29+00:00 2 Answers 0 views 0

TRẢ LỜI ( 2 )

  1. #andy
    \[\begin{array}{l}
    1){\rm{ }}135{\rm{ }} + {\rm{ }}360{\rm{ }} + {\rm{ }}65{\rm{ }} + {\rm{ }}24{\rm{ }} + {\rm{ }}40\\
     = (135 + 65) + (360 + 40) + 24\\
     = 200 + 400 + 24\\
     = 600 + 24\\
     = 624\\
    2){\rm{ }}8.{\rm{ }}4.{\rm{ }}34.{\rm{ }}125.{\rm{ }}25\\
     = (25.8)(125.4).34\\
     = 200.500.34\\
     = 3400000\\
    4){\rm{ }}129.{\rm{ }}172{\rm{ }} – {\rm{ }}73.{\rm{ }}129{\rm{ }} + {\rm{ }}129\\
     = 129.(172 – 73 + 1)\\
     = 129.100\\
     = 12900\\
    5)\,{5.2^3} – 18:{3^2}\\
     = 5.8 – 18:9\\
     = 40 – 2\\
     = 38\\
    6)205 – [1200 – {({4^2} – 2.3)^3}]:40\\
     = 205 – [1200 – {(16 – 6)^3}]:40\\
     = 205 – (1200 – {10^3}):40\\
     = 205 – (1200 – 1000):40\\
     = 205 – 200:40\\
     = 200
    \end{array}\]

  2. $@Zeng$
    $1)135+360+65+24+40$
    $=(135+65)+(360+40)+24$
    $=200+400+24$
    $=600+24$
    $=624$
    $2+3)8.4.34.125.25$
    $=(8.125).(4.25).34$
    $=1000.100.34$
    $=100000.34$
    $=3400000$
    $4)129.172-73.129+129$
    $=129(172-73+1)$
    $=129(99+1)$
    $=129.100$
    $=12900$
    $5.2^3-18:3^2$
    $=5.8-18:9$
    $=40-2$
    $=38$
    $6)205-[1200-(4^2-2.3)^3]:40$
    $=205-[1200-(16-2.3)^3]:40$
    $=205-[1200-(16-6)^3]:40$
    $=205-[1200-10^3]:40$
    $=205-[1200-1000]:40$
    $=205-200:40$
    $=205-5$
    $=200$
     

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