Toán Lớp 10: Định m để pt sau có nghiệm:
(mx – 3)[(m + 1)x – m] = 0
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Toán Lớp 10: Định m để pt sau có nghiệm:
(mx – 3)[(m + 1)x – m] = 0
Comments ( 2 )
\left( {mx – 3} \right)\left[ {\left( {m + 1} \right)x – m} \right] = 0\\
\to \left[ \begin{array}{l}
mx – 3 = 0\\
\left( {m + 1} \right)x – m = 0
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = \dfrac{3}{m}\\
x = \dfrac{m}{{m + 1}}
\end{array} \right.
\end{array}\)
\Leftrightarrow \left\{ \begin{array}{l}
m \ne 0\\
m + 1 \ne 0
\end{array} \right.\\
\to m \ne \left\{ { – 1;0} \right\}
\end{array}\)