Toán Lớp 8: x(x-2)+8-4x=0
x^2+9x=0
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Toán Lớp 8: x(x-2)+8-4x=0
x^2+9x=0
Helppp meeee
Comments ( 2 )
$\text{ ⇒ Tập nghiệm PT: S={2;4}}$
$⇔x^2-2x+8-4x=0$
$⇔x^2-6x+8=0$
$⇔x^2-6x+9-1=0$
$⇔(x-3)^2=1$
$⇔\left[ \begin{array}{l}x-3=1\\x-3=-1\end{array} \right.$
$⇔\left[ \begin{array}{l}x=4\\x=2\end{array} \right.$
$⇔x(x+9)=0$
$\left[ \begin{array}{l}x=0\\x+9=0\end{array} \right.$
$\left[ \begin{array}{l}x=0\\x=-9\end{array} \right.$