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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: (2x+3)^3 (1/2-y)^3 1/8a^3+27b^3 1/27a^3-8b^3 ai làm giúp em vs ạ

Home/ Toán Lớp 8: (2x+3)^3 (1/2-y)^3 1/8a^3+27b^3 1/27a^3-8b^3 ai làm giúp em vs ạ

Toán Lớp 8: (2x+3)^3 (1/2-y)^3 1/8a^3+27b^3 1/27a^3-8b^3 ai làm giúp em vs ạ

Tháng Chín 4, 2022 Toán học 2 Comments 0 views

Toán Lớp 8: (2x+3)^3
(1/2-y)^3
1/8a^3+27b^3
1/27a^3-8b^3
ai làm giúp em vs ạ

Comments ( 2 )

  1. maingocquynhnhu2k1
    maingocquynhnhu2k1
    4 Tháng Chín, 2022 at 10:43 sáng
    Reply
    a) $(2x+3)^3$
    $=(2x)^3+3.(2x)^2.3+3.2x.3^2+3^3$
    $=8x^3+36x^2+54x+8$
    b) $\Bigg(\dfrac{1}{2}-y\Bigg)^3$
    $=\dfrac{1}{8}-3.\dfrac{1}{4}.y+3.\dfrac{1}{2}.y^2-y^3$
    $=\dfrac{1}{8}-\dfrac{3}{4}y+\dfrac{3}{2}y^2-y^3$
    c) $\dfrac{1}{8}a^3+27b^3$
    $=\Bigg(\dfrac{1}{2}a\Bigg)^3+(3b)^3$
    $=\Bigg(\dfrac{1}{2}a+3b\Bigg)\Bigg(\dfrac{a^2}{4}-\dfrac{3ab}{2}+9b^2\Bigg)$
    d) $\dfrac{1}{27}a^3-8b^3$
    $=\Bigg(\dfrac{1}{3}a\Bigg)^3-(2b)^3$
    $=\Bigg(\dfrac{1}{3}a-2b\Bigg)\Bigg(\dfrac{a^2}{9}+\dfrac{2ab}{3}+4b^2\Bigg)$

  2. haiyemy
    haiyemy
    4 Tháng Chín, 2022 at 10:43 sáng
    Reply

    Đáp án
    toan-lop-8-2-3-3-1-2-y-3-1-8a-3-27b-3-1-27a-3-8b-3-ai-lam-giup-em-vs-a

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222-9+11+12:2*14+14 = ? ( )

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